Termination w.r.t. Q of the following Term Rewriting System could not be shown:
Q restricted rewrite system:
The TRS R consists of the following rules:
f1(g1(a)) -> a
f1(f1(x)) -> b
g1(x) -> f1(g1(x))
Q is empty.
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
f1(g1(a)) -> a
f1(f1(x)) -> b
g1(x) -> f1(g1(x))
Q is empty.
Q DP problem:
The TRS P consists of the following rules:
G1(x) -> F1(g1(x))
G1(x) -> G1(x)
The TRS R consists of the following rules:
f1(g1(a)) -> a
f1(f1(x)) -> b
g1(x) -> f1(g1(x))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ DependencyGraphProof
Q DP problem:
The TRS P consists of the following rules:
G1(x) -> F1(g1(x))
G1(x) -> G1(x)
The TRS R consists of the following rules:
f1(g1(a)) -> a
f1(f1(x)) -> b
g1(x) -> f1(g1(x))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
The approximation of the Dependency Graph contains 1 SCC with 1 less node.
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ DependencyGraphProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
G1(x) -> G1(x)
The TRS R consists of the following rules:
f1(g1(a)) -> a
f1(f1(x)) -> b
g1(x) -> f1(g1(x))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.